Excel BI - Excel Challenge 756

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excel-formulas

🔰 Words Answer Expected education e1du2ca3ti4o5n bats ba1ts audiovisual a1u2di3o4vi5su6a7l alien a1li2e3n

Published

March 24, 2026

Illustration for Excel BI - Excel Challenge 756

Challenge Description

🔰 Words Answer Expected education e1du2ca3ti4o5n bats ba1ts audiovisual a1u2di3o4vi5su6a7l alien a1li2e3n

Solutions

library(tidyverse)
library(readxl)

path = "Excel/700-799/756/756 Replace Vowels.xlsx"
input = read_excel(path, range = "A1:A9")
test  = read_excel(path, range = "B1:B9")

result = input %>%
  mutate(char = str_split(Words, "")) %>%
  unnest(char) %>%
  mutate(counter = ifelse(char %in% c("a", "e", "i", "o", "u"), 
                          cumsum(char %in% c("a", "e", "i", "o", "u")), 
                          NA_integer_), .by = Words) %>%
  unite("Word_c", char, counter, sep = "", remove = T, na.rm = T) %>%
  summarise(`Answer Expected` = paste(Word_c, collapse = ""), .by = Words)

all.equal(result$`Answer Expected`, test$`Answer Expected`, check.attributes = FALSE) 
# > [1] TRUE

Logic: Read the workbook ranges needed for the challenge; Derive the required intermediate columns; Parse the packed text or string structure; Aggregate or rank the data at the required grouping level.
Strengths: The code maps the workbook rule into a compact, reproducible pipeline.
Areas for Improvement: The solution assumes the workbook layout and selected ranges remain stable, so any structural change in the sheet would require small adjustments.
Gem: The elegant part is how little code is needed once the correct intermediate representation is chosen.

import pandas as pd

path = "700-799/756/756 Replace Vowels.xlsx"
input = pd.read_excel(path, usecols="A", nrows=9)
test = pd.read_excel(path, usecols="B", nrows=9)

def process_word(word):
    vowels = 'aeiou'
    word = str(word)
    count = 0
    result = []
    for c in word:
        if c in vowels:
            count += 1
            result.append(f"{c}{count}")
        else:
            result.append(c)
    return ''.join(result)

input['Answer Expected'] = input.iloc[:,0].apply(process_word)
result = input.rename(columns={input.columns[0]: 'Words'})[['Words', 'Answer Expected']]

print(result['Answer Expected'].equals(test['Answer Expected'])) # True

The Python version keeps the algorithm explicit, which helps when the challenge depends on a greedy or iterative rule.

Difficulty Level

Easy / Medium

The business rule is clear, though the workbook still needs a few transformation steps to reach the expected output.