library(tidyverse)
library(readxl)
path = "Excel/675 Permutations with signs.xlsx"
input = read_excel(path, range = "B2:C3")
test = read_excel(path, range = "B6:C13", col_names = c("Var1", "Var2")) %>% arrange(Var1, Var2)
a = input$num1
b = input$num2
as = c(a, -a)
bs = c(b, -b)
df = rbind(expand.grid(as, bs), expand.grid(bs, as)) %>% as.data.frame() %>%
arrange(Var1, Var2)
all.equal(df, test, check.attributes = FALSE)
#> [1] TRUEExcel BI - Excel Challenge 675
excel-challenges
excel-formulas
🔰 Given 2 input numbers, create all possible permutations considering numbers as both positive and negative.

Challenge Description
🔰 Given 2 input numbers, create all possible permutations considering numbers as both positive and negative.
Solutions
- Logic: Read the workbook ranges needed for the challenge.
- Strengths: The code maps the workbook rule into a compact, reproducible pipeline.
- Areas for Improvement: The solution assumes the workbook layout and selected ranges remain stable, so any structural change in the sheet would require small adjustments.
- Gem: The elegant part is how little code is needed once the correct intermediate representation is chosen.
import pandas as pd
import itertools
path = "675 Permutations with signs.xlsx"
input = pd.read_excel(path, usecols="B:C", nrows=2, skiprows=1)
test = pd.read_excel(path, usecols="B:C", skiprows=4, nrows=9, names=["Var1", "Var2"]).sort_values(by=["Var1", "Var2"]).reset_index(drop=True)
a, b = input.iloc[0, 0], input.iloc[0, 1]
combinations = list(itertools.product([a, -a], [b, -b])) + list(itertools.product([b, -b], [a, -a]))
results = pd.DataFrame(combinations, columns=['Var1', 'Var2']).sort_values(by=['Var1', 'Var2']).reset_index(drop=True)
print(results.equals(test)) # TrueThe Python version mirrors the same workbook logic with a concise, direct implementation.
Difficulty Level
Easy / Medium
The business rule is clear, though the workbook still needs a few transformation steps to reach the expected output.