library(tidyverse)
library(readxl)
library(hms)
test = read_excel("Power Query/PQ_Challenge_151.xlsx", range = "G1:H6") %>%
janitor::clean_names()
read_excel_range <- function(file, range) {
read_excel(file, range = range) %>%
mutate(across(c(starts_with("Start Time"), starts_with("End Time")), as_hms),
across(c(starts_with("Start Date"), starts_with("End Date")), as_date)) %>%
janitor::clean_names()
}
input1 <- read_excel_range("Power Query/PQ_Challenge_151.xlsx", "A1:E6")
input2 <- read_excel_range("Power Query/PQ_Challenge_151.xlsx", "A9:D14")
result <- input1 %>%
mutate(
start = as_datetime(start_date) + start_time,
end = as_datetime(end_date) + end_time,
datetime = map2(start, end, seq, by = "hour")
) %>%
unnest(datetime) %>%
mutate(
weekday = wday(datetime, week_start = 1),
time = as_hms(datetime)
) %>%
left_join(input2, by = "weekday") %>%
filter(datetime >= start & datetime <= end,
time >= start_time.y & time < end_time.y) %>%
group_by(employee) %>%
summarise(total_hours = n() %>% as.numeric())
identical(result, test)
#> [1] TRUEExcel BI - PowerQuery Challenge 151
excel-challenges
power-query
Employee Start Date Start Time End Date End Time Total Hours

Challenge Description
Employee Start Date Start Time End Date End Time Total Hours
Solutions
Logic:
Reads the workbook range needed for the challenge
Reshapes the data into the structure required by the result table
Aggregates or ranks values at the relevant grouping level
Builds helper columns that drive the final output
Strengths:
- The R solution stays close to the workbook logic and keeps the transformation compact.
Areas for Improvement:
- The code assumes the workbook layout and selected ranges remain stable.
Gem:
- The best part of the solution is choosing the right intermediate shape before formatting the final output.
import pandas as pd
test = pd.read_excel("PQ_Challenge_151.xlsx", usecols="G:H", nrows=6)
test.columns = [c.strip().lower() for c in test.columns]
def read_range(path, usecols, skiprows, nrows):
df = pd.read_excel(path, usecols=usecols, skiprows=skiprows, nrows=nrows)
df.columns = [c.strip().lower().replace(" ", "_") for c in df.columns]
return df
input1 = read_range("PQ_Challenge_151.xlsx", "A:E", 0, 6)
input2 = read_range("PQ_Challenge_151.xlsx", "A:D", 8, 6)
input1["start"] = pd.to_datetime(input1["start_date"]) + pd.to_timedelta(input1["start_time"].astype(str))
input1["end"] = pd.to_datetime(input1["end_date"]) + pd.to_timedelta(input1["end_time"].astype(str))
rows = []
for _, row in input1.iterrows():
rng = pd.date_range(row["start"], row["end"], freq="H")
for dt in rng:
rows.append({"employee": row["employee"], "start": row["start"], "end": row["end"], "datetime": dt})
result = pd.DataFrame(rows)
result["weekday"] = result["datetime"].dt.weekday + 1
result["time"] = result["datetime"].dt.time
input2["start_time"] = pd.to_timedelta(input2["start_time"].astype(str))
input2["end_time"] = pd.to_timedelta(input2["end_time"].astype(str))
result["time_td"] = pd.to_timedelta(result["time"].astype(str))
result = result.merge(input2, on="weekday", how="left")
result = result[(result["datetime"] >= result["start"]) & (result["datetime"] <= result["end"]) & (result["time_td"] >= result["start_time"]) & (result["time_td"] < result["end_time"])]
result = result.groupby("employee", as_index=False).size().rename(columns={"size": "total_hours"})
print(result.equals(test))Logic:
Reads the workbook range needed for the challenge
Aggregates or ranks values at the relevant grouping level
Applies the rule iteratively until the output is complete
Strengths:
- The Python version follows the same workbook rule in a direct pandas-oriented implementation.
Areas for Improvement:
- As with the R version, any workbook layout change would require small adjustments.
Gem:
- The implementation stays close to the source challenge instead of adding unnecessary abstraction.
Difficulty Level
This task is moderate:
It combines reshaping, grouping, or parsing steps that are common in Power Query style problems.
The main challenge is reproducing the workbook output structure exactly.